DMD 0.148 release

[Thomas Kuehne]

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Regan Heath schrieb am 2006-02-26:
> On Sun, 26 Feb 2006 18:46:10 +0000 (UTC), Thomas Kuehne  
><thomas-dloop at kuehne.cn> wrote:
>> Charles schrieb am 2006-02-26:
>>>
>>> > Can't we simply treat zero as false and non-zero as true as we C
>>> > programmers always do?
>>>
>>> I agree, I still don't get what the 'true bool' fuss is about .
>>
>> if(b==1) { ... }
>>
>> instead of
>>
>> if(b!=0) { ... }
>>
>> can be found in quite a lot of C code ...
>
> So?
>
> Assuming:
>
>   - 'b' is a bool
>   - a bool can only have 2 values, 'true' and 'false'
>   - when you convert/promote a bool to an int you get: 'true'->'1',  
> 'false'->'0'
>   - when you convert/promote an int to bool you get: '0'->false,  
> '!0'->'true'
>
> Then:
>
> if(b==1) { ... }
>
> results in 'b' being converted to int, giving it the value 1, and the  
> comparrison working correctly.
>
> Right?


# import std.stdio;
#
# int main(){
#	int i = 3;
#	bool a = true;
#	bool b = *(cast(bool*)cast(void*) &i);
#
#	writefln("a: %s", a);
#	writefln("b: %s", b);
#	writefln("int: %s", cast(int)b); // line 9
#	writefln("a+b: %s", a+b); // line 10
#
#	return 0;
# }

I know, nobody writes code like that ...

surprise:
true -> 3 // line 9
true + true -> 4 // line 10

>   - when you convert/promote a bool to an int you get: 'true'->'1',  
> 'false'->'0'

The problem is: that assumtion isn't easily enforcable if bool is
treated as an integer type.

Thomas


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