[Issue 274] New: Different template alias arguments are treated as the same.

d-bugmail at puremagic.com d-bugmail at puremagic.com
Tue Aug 1 16:50:15 PDT 2006


http://d.puremagic.com/issues/show_bug.cgi?id=274

           Summary: Different template alias arguments are treated as the
                    same.
           Product: D
           Version: 0.163
          Platform: PC
        OS/Version: Windows
            Status: NEW
          Keywords: wrong-code
          Severity: critical
          Priority: P1
         Component: DMD
        AssignedTo: bugzilla at digitalmars.com
        ReportedBy: daiphoenix at lycos.com


Under certain conditions, different template alias arguments are treated as the
same, and thus fail to create different template instances. Consider this code:

----
import std.stdio;

class Foo {} 
class Bar {}

template aliastest(alias A) {
        pragma(msg,"Alias Test instanciated");  
        void aliastest() {
                writefln("Alias Test: ", (new A!().al).classinfo.name);
        }
}

template boxtpl(alias A) {
        template box() {
                alias A al;
        }
}

void test() {
        aliastest!(boxtpl!(Foo).box) ();
        aliastest!(boxtpl!(Bar).box) ();
        aliastest!(boxtpl!(Exception).box) ();
}
----

In the test function, aliastest is only instantiated once (we only see the
pragma msg once), and both instances are considered to be the same, such that
the runtime output is: 
  Alias Test: Foo
  Alias Test: Foo
  Alias Test: Foo

That is, "aliastest!(boxtpl!(Bar).box)" and any other subsequent atempted
instantiations of the form "aliastest!(boxtpl!(XXXX).box)" are considered to be
the same as the first one, the one with alias argument "boxtpl!(Foo).box".


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