[Issue 1179] Compiler doesn't complain about function redefinition when using template mixin

Aarti_pl aarti at interia.pl
Tue Apr 24 00:54:21 PDT 2007


d-bugmail at puremagic.com napisał(a):
> http://d.puremagic.com/issues/show_bug.cgi?id=1179
> 
> 
> bugzilla at digitalmars.com changed:
> 
>            What    |Removed                     |Added
> ----------------------------------------------------------------------------
>              Status|NEW                         |RESOLVED
>          Resolution|                            |INVALID
> 
> 
> 
> 
> ------- Comment #1 from bugzilla at digitalmars.com  2007-04-23 14:04 -------
> This is the way its supposed to work. Each mixin gets its own namespace, so
> that names can match names in the non-mixin declarations and other mixin
> declarations. You can access those conflicting names by using the mixin name as
> a scope operator.
> 
> 

Probably below cite would be more appropriate to describe why my bug was 
invalid:  :-))  (I don't know any way to access anonymous mixin members 
- if there is a way to do it I would be happy to know how...)

---
Mixin Scope
The declarations in a mixin are 'imported' into the surrounding scope. 
If the name of a declaration in a mixin is the same as a declaration in 
the surrounding scope, the surrounding declaration overrides the mixin one.
---

Sorry about invalid bug report. Something strange is happening with 
mixins in my program, so I thought that it was reason. But it must be 
something else. I will try to find it out and report in another bug report.


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