[Issue 1073] New: CTFE: mixin expression with a function argument doesn't work

[d-bugmail at puremagic.com]

http://d.puremagic.com/issues/show_bug.cgi?id=1073

           Summary: CTFE: mixin expression with a function argument doesn't
                    work
           Product: D
           Version: 1.009
          Platform: PC
        OS/Version: Windows
            Status: NEW
          Severity: normal
          Priority: P2
         Component: DMD
        AssignedTo: bugzilla at digitalmars.com
        ReportedBy: torhu at yahoo.com


This code checks if TEST is defined, and defines it if not.  If using the line
that's commented out instead of the one above it, it works as expected.

---
const int TEST = 1;

char[] def(char[] s) {
    if (!is(typeof(mixin(s))))  // doesn't detect that TEST is defined
    //if (!is(typeof(mixin("TEST"))))  // this works fine
        return "const int " ~ s ~ " = 3;\n";
    else return "";
}

mixin(def("TEST"));

void main() { }
---

test.d: variable test.TEST conflicts with test.TEST at test.d(1)


I tried to recreate this problem without CTFE, just with a static if, but it
doesn't happen then.


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