[Issue 664] is(func T == function) ignores variadic arguments

d-bugmail at puremagic.com d-bugmail at puremagic.com
Mon Dec 19 04:59:49 PST 2011


http://d.puremagic.com/issues/show_bug.cgi?id=664



--- Comment #6 from Don <clugdbug at yahoo.com.au> 2011-12-19 04:59:44 PST ---
(In reply to comment #5)
> (3) Have function(char, ...) just not matching function(T) for any value of T. 
> ... is a fundamentally different kind of thing from a type, so it doesn't seem
> to make sense to allow it as an element of a type tuple.


How does that solve the problem? The root cause is that is( ==function) assumes
that all of the function parameters can be returned in a tuple, but that isn't
true for ...
Or do you mean that is( x==function) should be an error if x has a variadic
parameter?

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