[Issue 664] is(func T == function) ignores variadic arguments

[d-bugmail at puremagic.com]

http://d.puremagic.com/issues/show_bug.cgi?id=664



--- Comment #8 from Don <clugdbug at yahoo.com.au> 2011-12-19 22:34:00 PST ---
(In reply to comment #7)
> (In reply to comment #6)
> > How does that solve the problem? The root cause is that is( ==function) assumes
> > that all of the function parameters can be returned in a tuple, but that isn't
> > true for ...
> 
> In what way does it make that assumption?

It declares T as a tuple containing all of the function arguments.

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