[Issue 10755] 'has no effect in expression' error for return too with comma operator

[d-bugmail at puremagic.com]

https://d.puremagic.com/issues/show_bug.cgi?id=10755


yebblies <yebblies at gmail.com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
                 CC|                            |yebblies at gmail.com


--- Comment #1 from yebblies <yebblies at gmail.com> 2014-02-05 22:43:16 EST ---
There is some dead code in sideeffect.c that implements this:


/* This isn't used yet because the only way an expression has an unused
sub-expression
 * is with the CommaExp, and that currently generates messages from rewrites
into comma
 * expressions. Needs more investigation.
 */
void Expression::useValue()
{
#if 0
    // Disabled because need to cast(void) the a,b code generation
    void *p;
    apply(&lambdaUseValue, &p);
#endif
}

#if 0
int lambdaUseValue(Expression *e, void *param)
{
    switch (e->op)
    {
        case TOKcomma:
        {   CommaExp *ce = (CommaExp *)e;
            discardValue(ce->E1);
            break;
        }

        default:
            break;
    }
    return 0;
}
#endif

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