[Issue 12154] New: Address of a member function doesn't tell about this - breaks std.concurrency

[d-bugmail at puremagic.com]

https://d.puremagic.com/issues/show_bug.cgi?id=12154

           Summary: Address of a member function doesn't tell about this -
                    breaks std.concurrency
           Product: D
           Version: D2
          Platform: All
        OS/Version: All
            Status: NEW
          Severity: normal
          Priority: P2
         Component: DMD
        AssignedTo: nobody at puremagic.com
        ReportedBy: destructionator at gmail.com


--- Comment #0 from Adam D. Ruppe <destructionator at gmail.com> 2014-02-13 13:51:58 PST ---
http://stackoverflow.com/questions/21765885/the-this-pointer-and-message-receiving-in-d/21766122#21766122


Currently, this compiles:

class Foo {
        void bar(int) {}
}

static assert(is(typeof(&Foo.bar) == void function(int)));


But if you actually try to use it, you get a problem:

void main() {
        void function(int) fn = &Foo.bar;
        fn(10);
}
$ ./test52
Segmentation fault


Being a non-static member variable, it expects a context pointer to be passed
to it as well, but there's no indication of that in the returned type.

I think it should actually be typed void function(int, Foo); or something like
that. Otherwise, generic code that tries to look at the type,
std.concurrency.receive for example, can try to blindly use it and get runtime
crashes where i think it should be a type system error.

It also cannot be a delegate at this point because the context pointer is
unknown.


The exception is if you are already in a non-static method and refer to it:

class Foo {
        void bar(int a) {
                import std.stdio;
                writeln(a);
        }
}
class Baz : Foo {
        override void bar(int) {
                Foo.bar(1); // calls the method from the super class
        }
}


In this case, the address-of operator already yields void delegate(int a) -
which works and makes sense.

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