Weird (?) problem

[Ary Manzana]

mike wrote:
> Thanks, it works! :-)
> 
> I still need one little workaround, but that's ok.
> 
> Funny thing is: Thinking about it a little bit more I got that idea:
> 
> ' class TypeFoo : TypeBase
> ' {
> '     public:
> '         static this() { instance = new Bar(); }
> '
> '     private:
> '         void setup() { /* add object, setup */ }
> '         TypeBase instance;
> '
> '     unittest
> '     {
> '         instance.setup();
> '     }
> ' }
> 
> since the unittest will be executed after ALL static this()'s are done, 
> and it's the only piece of code that is tied to a class and called 
> automatically (besides the constructors) - but I don't want to be that 
> evil :-)

Watch out!! Unit tests are only for debug purposes, once you compile 
your code with the "release" flag, no unit test will ever be invoked.

> 
> Another question:
> 
> Is there a way to prevent a derived class from calling super()? I solved 
> this currently with an empty this(int) and calling super(0), but is 
> there another way?

I believe not, and it's because of the OOP philosophy... But you can 
always make a protected constructor for your derived classes, although 
this increases code dependency between classes, and I don't recommend it.

> 
> -Mike
> 
> 
> Am 10.08.2006, 14:14 Uhr, schrieb Ary Manzana <asterite at gmail.com>:
> 
>> Have you tried placing code after "instance = new TypeType()"?
>>
>> Like this:
>>
>> ' class TypeType : TypeBase
>> ' {
>> '     TypeBase instance = null;
>> '     static this() {
>> '         instance = new TypeType();
>> '         // I don't know whether addObject is a function
>> '         // or a member of TypeType, but you get the point
>> '         instance.addObject("typetype");
>> '         instance.getObject("typetype").setType(instance);
>> '     }
>> '     static TypeBase opCall() { return instance; }
>> '     this()
>> '     {
>> '     }
>> ' }
>>
>> Hope that helps (and works).
>> Ary
> 
> 
> 
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