Function overloading question

[Márcio Faustino]

Kirk McDonald wrote:
> void foo(int) {}
> void foo(double) {}
> 
> There are two ways:
> 
> void function(int) fn1 = &foo;
> void function(double) fn2 = &foo;
> 
> These will each get the proper overloads. Alternately:
> 
> auto fn3 = cast(void function(int)) &foo;
> auto fn4 = cast(void function(double)) &foo;
> 
> This will also work.
> 

Thanks!