Save a type in a variable

[pragma]

Kirk McDonald wrote:
> Pragma wrote:
>> Heinz wrote:
>>
>>> Hi, i have a class and i need to retrieve a type as a parameter in 
>>> its constructor, example: (can be made easily in c#)
>>>
>>> class myclass
>>> {
>>>         type mytype;
>>>                 this(type t)
>>>         {
>>>                  mytype = t;
>>>         }
>>> }
>>>
>>> I don't have a single approach to do this. i need a clue pliss? an 
>>> example woyld be great hehe, thx
>>
>>
>> You want to use 'TypeInfo' at runtime (instead of 'type'), and use 
>> typeof(T) at compile time:
>>
>> for example:
>>
>> TypeInfo mytype = typeof(int);
>>
>>
> 
> That should be:
> 
> TypeInfo mytype = typeid(int);
> 
> typeid() returns a type's TypeInfo at runtime. typeof() infers the type 
> of an expression at compile-time.
> 
> Note that TypeInfo is just information about a type. (You can compare 
> the TypeInfos of two items to see if they are the same type.) You cannot 
> create variables of a type with just its TypeInfo. (That kind of 
> trickery is what templates are for.)
> 
ack... um, what he said. :)

sorry for the misinformation.