still confused about call by reference

[Saaa]

>> Saaa wrote:
>>> What does this mean exactly ?
>>>
>>> initialize an instance of a struct on the heap
>>> without factoring out the initialization to _another_ function
>>
>> You can say
>>   MyStruct *x = new MyStruct;
>>
>> But even with a static opCall defined, this doesn't work
>>   MyStruct *x = new MyStruct(a,b,c);
>>
>> You have to do something like:
>>   MyStruct *x = new MyStruct;
>>   *x = MyStruct(a,b,c);
>>
>> Or that's what I guess he means, at least.  I haven't actually tried the 
>> code above to see what it will do.
>>
>> --bb
>
> I was thinking more along the lines of
>
> struct S
> {
>    int x, y;
>
>    void init(int x, int y)
>    {
>        this.x = x;
>        this.y = y;
>    }
>
>    static S opCall(int x, int y)
>    {
>        S s;
>        s.init(x, y);
>        return s;
>    }
> }
>
> ..
>
> // Stack
> S s = S(3, 4);
>
> // Heap
> S* t = new S;
> t.init(5, 6);
>

Ah, I see what you mean.
making your own _new would fix this, right? But yeah I think a constructor 
would be much better ;)
I always put everything on the stack for speed purposes. I now that I think 
about it, I also never throw any struct array away.
I try to allocate all necessary memory at the beginning of my programs.
Ticks are allot more scarce than memory in my programs :D
Anyway thanks.