identic ref/inout parameter

[Downs]

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Regan Heath wrote:
> Wilhelm wrote:
>> Who do I determine in a function (probably with a assert statement)
>> that the function with more the one ref/inout parameters of the same
>> type are not called with the same variable like:
>>
>> private import std.stdio;
>>
>> int main(char[][] args)
>> {
>>     int i=3;
>>     test( i,i,i,i);
>>     return 0;
>> }
>>
>>
>> void test(ref int r1, ref int r2, inout int i1, inout int i2)
>> {
>>     writefln ("           Ref: r1=%d r2=%d", r1, r2);
>>     writefln ("         InOut: i1=%d i2=%d", i1, i2);
>>     r1 += 2;
>>     writefln ("r1 += 2;   Ref: r1=%d r2=%d", r1, r2);
>>     writefln ("r1 += 2; InOut: i1=%d i2=%d", i1, i2);
>>     i2 += 2;
>>     writefln ("i1 += 2;   Ref: r1=%d r2=%d", r1, r2);
>>     writefln ("i1 += 2; InOut: i1=%d i2=%d", i1, i2);
>> }
>>
>> !! That may cause interesting results !!
> 
> Maybe...
> 
>     assert(&r1 != &r2);
>     assert(&r1 != &i1);
>     assert(&r1 != &i2);
>     assert(&r2 != &i1);
>     assert(&r2 != &i2);
>     assert(&i1 != &i2);
> 
> Regan
To clean it up a little

void assertUnique(T)(ref T[] values...) {
  foreach (index, ref value; values[0..$-1])
    foreach (ref value2; values[index+1..$])
      assert(&value != &value2);
}

Untested, but should work.
 --downs
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