Behaviour of %08X format specifiers on addresses
Graham
grahamc001uk at yahoo.co.uk
Sat Sep 22 05:28:09 PDT 2007
Being used to printing addresses in "C" as 8 hex digits I though the behavior of this code a little unexpected:
import std.stdio;
void main(char[][] args) {
char* p;
int n;
p = cast(char*) 1;
writefln("p = %08X", p);
n = 1;
writefln("n = %08X", n);
p = cast(char*) 0x12;
writefln("p = %08X", p);
n = 0x12;
writefln("n = %08X", n);
p = cast(char*) 0x1234;
writefln("p = %08X", p);
n = 0x1234;
writefln("n = %08X", n);
p = cast(char*) 0x123456;
writefln("p = %08X", p);
n = 0x123456;
writefln("n = %08X", n);
p = cast(char*) 0x12345678;
writefln("p = %08X", p);
n = 0x12345678;
writefln("n = %08X", n);
}
which displays:
p = 0001
n = 00000001
p = 0012
n = 00000012
p = 1234
n = 00001234
p = 123456
n = 00123456
p = 12345678
n = 12345678
I presume this is intentional (not always displaying the leading zeros on addresses).
Is it documented anywhere that this is how it should behave ?
I am running the v1.015 compiler on a Windows platform.
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