Why not mixin "int a;" ??
Tomasz Sowiñski
tomeksowi at gmail.com
Sun Aug 24 15:42:53 PDT 2008
Jarrett Billingsley Wrote:
> mixin foo;
>
> This is now grammatically ambiguous. If foo is a const char[], then it's a
> string mixin. If foo is a template, then it's the same as "mixin foo!();".
> This could be disambiguated later, but..
>
Is there a difference in what happens when you mixin a template and a string?
I still don't see why this distinction is necessary.
Tomek
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