passing all writefln arguments

Saaa empty at needmail.com
Thu Mar 20 17:18:09 PDT 2008


Seems to work, thanks.


> Saaa wrote:
>> Thanks,
>>
>> As I think that changing a variable is easier than changing the compiler 
>> line I went with:
>>
>> const bool DEBUGG=false;
>>
>> static if (DEBUGG == true) {
>>  alias writefln dWritefln;
>> }
>> else {
>>  void dWritefln(...) {}
>> }
>
> I think you can set debug versions inside a file too.  That way you can 
> have the best of both worlds.  Turn it on from the command line, or by 
> modifying the file.
>
> debug = DEBUGG;
>
> debug(DEBUGG) {
>  alias writefln dWritefln;
> }
> else {
>  void dWritefln(...) {}
> }
>
> ... at least that works with 'version'.  Not sure if it works with debug 
> too.  (If it doesn't I'll file a bug about the inconsistency with 
> 'version'.)
>
>> Will dWritefln(..){} compile to 'nothing'?
> > I mean, will calling dWritefln when DEBUGG=false take no cpu tick
> (does the
> > compiler see that it does nothing)?
>
>
> Yes.  See thread entitled "debug()" over in digitalmars.D.
> digitalmars.com digitalmars.D:66826
> digitalmars.com digitalmars.D:66827
>
> But that may only be with -inline.  Not sure what flags Jarrett used when 
> he ran the test.
>
> --bb 




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