bytes into integer, need help
James
James at gmail.com
Thu Nov 6 15:38:44 PST 2008
Steven Schveighoffer Wrote:
> "James" wrote
> > im having problem in code below, while making my own file handler. the
> > data stored in buffer, so i can recall portion of data in diff format and
> > length like int,short,etc. but im stuck with function getb() below. any
> > suggestion? thks.
> >
> > struct T_FILE_RAM {
> > ubyte[] buffer;
> > int offset;
> >
> > void getb(void* buf, int size) {
> > buf=&b[offset..offset+size]; //<-- prob here
> > }
> >
> > void read(out uint x) { getb(&x, x.sizeof); }
> > void read(out ushort x) { getb(&x, x.sizeof); }
> >
> > }
>
> I think you meant this?
>
> buf[0..size] = buffer[offset..offset+size];
> And also, you need to increment offset, no?
> offset += size.
>
> I'd also recommend using a template:
>
> void getb(T)(ref T t)
> {
> auto size = t.sizeof;
> auto buf = (cast(ubyte *)&t)[0..size];
> buf[] = buffer[offset..offset+size];
> offset += size;
> }
>
> Now you don't need to implement each type, and you can call like this:
> int x;
> ushort y;
> getb(x); // reads 4 bytes
> getb(y); // reads 2 bytes
>
> -Steve
>
>
thanks, exactly what im looking for. endianness isnt a problem at this point as im not working on a portable project.
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