Overloaded opApply for named template mixin
Simen Kjaeraas
simen.kjaras at gmail.com
Wed Nov 12 05:33:52 PST 2008
On Wed, 12 Nov 2008 11:37:33 +0100, Christian Hartung
<christian.s77 at gmail.com> wrote:
> Currently the right way to do this is:
>
> template foo(T)
> {
> int opApply(int delegate(ref T) dg)
> {
> // code
> }
> }
>
> class bar(T)
> {
> mixin foo!(T);
> }
>
> void main()
> {
> auto b = new bar!(int);
> foreach(qux; b)
> {
> }
> }
>
Ah, but that does not give me the named mixin.
Consider
class Tree(T)
{
mixin Traverse!(Stack) depthfirst;
mixin Traverse!(Queue) breadthfirst;
}
--
Simen
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