Thu, 06 Aug 2009 10:56:33 -0400, lllTattoolll wrote:
> hi Lars and thx for help. I fix a little the first problem, now I paste a verion in english whit coment because i´m lost here.
> the example is the same only this is in english for your compresion of my problem.
>
> --------------------------------------------------
> code
> -------------------------------------------------
>
> import std.stdio;
> import std.string;
> import std.c.stdio;
>
> void main()
> {
>
> string _name, _lastname, _response;
> int _age, _year, _birth;
> _year = 2009;
>
> writef ("Name: ");
> _name = readln().chomp;
>
> writef ("Lastname: ");
> _lastname = readln().chomp;
>
> writefln ("Hello %s ", _name, _lastname ); /* here is my first problem, dont show me the last name or show me in
> two lines ( this fix whit .chomp ) */
The format string must be "Hello %s %s" to display both operands. Or
you can use writeln instead:
writeln("Hello ", _name, " ", _lastname);
> writefln ("Year of birth: ");
> scanf ("%d", & _birth);
You use scanf here. Scanf only reads the number, and leaves the <Enter>
symbol in the input stream. When you later call readln() it sees that
<Enter> from the previous question and exits immediately. You better
use readln() everywhere:
_birth = std.conv.to!int(readln().chomp);
> _age = _year - _birth;
>
> writefln ("Your age is %d? \t YES \t NO", _age ); /* here is my second problem, can´t into the response and program*/
> _response = readln(); /* show me else line always */
>
> if ( chomp(_response) == "yes")
> writefln ("thank you %s", _name );
> else
> writefln ("Sorry %s you have %d", _name, _age - 1 ); /* this line always show me because can´t validate _response */
> }
The rest seems to work correctly.