array questions

[yes]

> 
> > Hello again
> > 
> > is it possible to make a dynamic array less dynamic?
> > 
> > int[][] array;
> > 
> > array[0].length = 10; //has to be set at runtime
> 
> Um, if that's your code, everything should crash at this point (or throw
> in debug mode): array is null, that is, empty, so there is no array[0].
> 
> You should array.length = 10; first.  Then you'll get an array of 10
well, at least to 2. my fault.
> empty arrays of int, and will be able to set their lengths separately:
> 
> array[0].length = 10; // OK
> assert(array[1].length == 0); // OK
> 
> If you want to set up quickly you can write
> 
> int[][] array = new int[][](10, 10);
thank you, that will make all the element to be at least a certain size.
> 
> This will give you a sort of square matrix, bit internally it will be an
> array of arrays nevertheless.
> 
> > also, can this be done?
> > 
> > int size;
> > size = 10; //runtime
> > void function( int[size][] array){}
> 
> No, static arrays are static, i.e. compile time.
I meant it to be an dynamic array argument, but that the function wouldn't need to check the size of all the elements itself.