[D1] type of type

[%u]

== Quote from Steven Schveighoffer (schveiguy at yahoo.com)'s article
> On Thu, 23 Dec 2010 17:28:49 -0500, %u <e at ee.com> wrote:
> > Should have been this:
> >
> > void func(type t){
> >   new t();
> > }
> void func(T)(){
>     new T();
> }
> When you are passing types into functions, use templates.
> -Steve

The reason I asked for a non-templated solution is because they don't have a
common interface signature.