Detecting a property setter?

[Simen kjaeraas]

Rory McGuire <rmcguire at neonova.co.za> wrote:

> Does anyone know how to detect if there is a setter for a property? The
> code below prints the same thing for both
> the setter and the getter of "front":
>
> ==============================
> import std.traits;
>
> class Foo {
>      uint num;
>
>      @property ref uint front() {
>          return num;
>      }
>      @property void front(uint i) {
>          num = i;
>      }
>
>      ref uint front2() {
>      	return num;
>      }
> }
>
> template isProperty(alias func) if (isCallable!(func)) {
> 	enum isProperty = (functionAttributes!(func) &
> FunctionAttribute.PROPERTY)==0 ? false : true;
> }
>
> template hasSetter(alias func) if (isCallable!(func)) {
> 	enum hasSetter = (isProperty!(func) && ParameterTypeTuple!(func).length  
> >
> 0 && ReturnType!(func).stringof != "void") ? true : false;
> }

For what it's worth, I would simply check if the property allows  
assignment. i.e.:

template hasSetter(alias func) if (isCallable!(func)) {
     enum hasSetter = isProperty!(func) &&
         is( typeof( (){ func = ReturnType!(func).init; } ) );
}

-- 
Simen