Type literal of pure function pointer

[Simen kjaeraas]

On Sun, 25 Jul 2010 01:10:54 +0200, bearophile <bearophileHUGS at lycos.com>  
wrote:

> In the following D2 the D type system is strong enough to allow foo1()  
> to be pure because sqr() is a pointer to a pure function. In foo2() I  
> have tried to do the same thing avoiding templates, and it works. In  
> foo3() I have tried to write the type literal, but I was not able to:
>
>
> pure int sqr(int x) {
>     return x * x;
> }
> pure int foo1(TF)(TF func, int x) { // OK
>     return func(x);
> }
> pure int foo2(typeof(&sqr) func, int x) { // OK
>     return func(x);
> }
> pure int foo3(pure int function(int) func, int x) { // line 10, ERR
>     return func(x);
> }
> void main() {
>     assert(foo1(&sqr, 5) == 25);
>     assert(foo2(&sqr, 5) == 25);
>     assert(foo3(&sqr, 5) == 25);
> }
>
>
> Errors given, dmd 2.047:
> test.d(10): basic type expected, not pure
> test.d(10): found 'pure' when expecting ')'
> test.d(10): semicolon expected following function declaration
> test.d(10): no identifier for declarator int function(int)
> test.d(10): semicolon expected, not 'int'
> test.d(10): semicolon expected, not ')'
> test.d(10): Declaration expected, not ')'
> test.d(12): unrecognized declaration
>
> (If you can't find a way to write that then I'll add it to Bugzilla.)
>
> Bye and thank you,
> bearophile


Add it to Bugzilla. Another case is that this works:

alias pure int function( int ) FN;
pure foo4( FN fn, int x ) {
     return fn( x );
}

It seems the problem is that type specification in function signatures
does not support the full range of type signature in the language.

-- 
Simen