Best way to make Until! into string

[Jonathan M Davis]

Okay. If you call until like so

str.until('\"')

you get a Until!(pred,string,char). I want to turn that into a string. 
array() doesn't seem to do the trick right now. It used to work, but now it 
gives me

main.d(47): Error: template std.array.array(Range) if (isForwardRange!
(Range)) does not match any function template declaration
main.d(47): Error: template std.array.array(Range) if (isForwardRange!
(Range)) cannot deduce template function from argument types !()(Until!
(pred,string,char))

to!string just converts it into a string with the Until! stuff being 
included in the string rather than giving me the actual result, so that 
doesn't work.

So, what is the correct and preferred way to convert the result of Until! to 
as string when you were searching on a string in the first place? The 
std.algorithm functions are definitely nice, but they have tendancy to 
return hard-to-use types.

- Jonathan M Davis