[D1] modulo on neg integer
qw at er.ty
Thu Mar 18 05:54:12 PDT 2010
> qwerty wrote:
> > If memory serves me right, module is undefined on negative integers.
> > int i = -2;
> > i%=10; // i=undefined?
> It's not undefined. x%y always has the sign of x, so i will be -2.
> This always holds:
> x == y * (x/y) + (x%y);
> And since D uses truncated division, the result follows.
> This behaviour is inherited from C99.
Ok, that seems sensible.
Yay,found the spec (mul expressions ?:):
"For integral operands of the / and % operators, the quotient rounds towards zero and the remainder has the same sign as the dividend. If the divisor is zero, an Exception is thrown. "
Personally I find your explanation a lot more clear :)
> > What should I use instead to get i definitely equal to 7?
> You mean 8?
> i %= 10;
> if (i<0) i += 10;
> > On a sidenote, where can I read about operation order/definitions?
> > Like i++, ++i and i%10 not changing i etc.
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