-static and dmd

[Jonathan M Davis]

Ali Çehreli wrote:

> Jonathan M Davis wrote:
>> With gcc, you can pass it the -static flag and it will statically link
>> everything. Normally, with dmd (on linux at least), it dynamically links
>> all of the C/C++ libraries that it uses. So, if I run ldd (well, ldd32
>> technically) on one of my programs I get:
>> 
>>         linux-gate.so.1 =>  (0xf7794000)
>>         libpthread.so.0 => /lib32/libpthread.so.0 (0xf7756000)
>>         libm.so.6 => /lib32/libm.so.6 (0xf7730000)
>>         libc.so.6 => /lib32/libc.so.6 (0xf75ea000)
>>         /lib32/ld-linux.so.2 (0xf7795000)
>> 
>> If it were gcc and -static had been used, you'd get
>> 
>>         not a dynamic executable
>> 
>> I'd like to be able to do the equivalent of -static with dmd so that my
>> dmd- generated binaries don't have to link against any of the C/C++
>> libraries on my system. Is there a way to do that? I can't see any.
>> Certainly, none of dmd's options appear to give that kind of
>> functionality. So, if there is a way to do it, I'd like to know how. Does
>> anyone here know how?
>> 
>> - Jonathan M Davis
> 
> A friend hit the same problem recently and I was able to achieve it by
> performing the linking step with gcc.
> 
> 1) Compile with dmd:
> 
>    dmd -c deneme.d -ofdeneme.o
> 
> 2) Link with gcc:
> 
>    gcc deneme.o -static -o deneme ~/dmd/linux/lib/libphobos2.a -lpthread
> 
> Worked with my simple test application.
> 
> Ali


Thanks! That seems to have done the trick. It's a pity that it doesn't 
appear to be doable with dmd directly though. I should probably create an 
issue for it on the bug tracker.

- Jonathan M Davis