[D1][expressions] Order Of Evaluation

[Denis Koroskin]

On Fri, 08 Oct 2010 18:49:36 +0400, %u <e at ee.com> wrote:

> /The following binary expressions are evaluated in an  
> implementation-defined
> order:
> AssignExpression/../AddExpression/
>
> /It is an error to depend on order of evaluation when it is not  
> specified./
>
> That makes this an error!?
>
> y = x + 1;
>
> Am I being paranoid or should I be adding more brackets?

Assignment has higher precedence that addition so your code has no errors.

However, the following one does:

int x = 1;
int y = (x = 2) + x;

because "x" and "x = 2" has same precedence and thus may be evaluated in  
any order.

Stay away from such code and you should be fine.