ElementType!(Range) problem

[Ishan Thilina]

--Philippe wrote::

>ElementType acts on types. It takes a type and 'returns' (compiles to,
>actually) another type. You need to give it typeof(listR).
>Then, as ElementType!(typeof(listR)) is a type, you cannot pass it to
>writeln. Use .stringof to go from the type to a string representation
>of its name.
>
>So:
>
>writefln("%s", ElementType!(typeof(listR)).stringof);
>
>ElementType!(typeof(listR)) is a type like any other. You can create a
>variable with it:
>
>ElementType!(typeof(listR)) elem;
>

Got it!. Thanks.

I faced this confusion because of the description for "ElementType" which is
available in http://d-programming-language.org/phobos/std_range.html. It says,

"
template ElementType(R):

The element type of R. R does not have to be a range. The element type is
determined as the type yielded by r.front for an object r or type R. For example,
ElementType!(T[]) is T. If R is not a range, ElementType!R is void.

"
So I thought that just passing ElementType!listR was adequate. :s