Is std.array.replace supposed to work with char[]?

[Steven Schveighoffer]

On Sun, 20 Feb 2011 14:51:10 -0500, bearophile <bearophileHUGS at lycos.com>  
wrote:

> Jacob Carlborg:
>
>> Every time I try to use D2 it's just a PITA to use. I've used D1 and  
>> Tango for
>> several years and had no problem with that.
>
> I use this thread to ask regarding one specific little problem I have  
> with strings. I want to generate a random string of AB using the array,  
> map, etc, this looks like a possible implementation (in std.random there  
> is no choice() function yet):
>
>
> import std.stdio, std.random, std.string, std.algorithm, std.range;
> void main() {
>     auto m = map!((i){ return "AB"[uniform(0,2)]; })(iota(10));
>     string s = join(array(m));
>     writeln(s);
> }
>
>
> It gives this error:
> ...\dmd\src\phobos\std\array.d(62): Error: result[i] isn't mutable
> test.d(5): Error: template instance  
> std.array.array!(Map!(__dgliteral1,Iota!(int,uint))) error instantiating
>
> What's the right way to write it in D?
>
> The same code in Python2.x:
>
> from random import choice
> s = "".join(choice("AB") for _ in xrange(10))
> print s

Just a blind guess, I have not tested, but maybe it's because the compiler  
is using const(char) as the return type for your delegate literal since  
you never specify one?

-Steve