Multiple opCall's

Mafi mafi at example.org
Mon Feb 21 02:47:03 PST 2011


Am 21.02.2011 11:18, schrieb useo:
> Hey guys,
>
> I've a small problem implementing multiple opCall()-methods. At first, I've the following interface:
>
> interface Invoker {
>   void opCall(uint i);
> }
>
> ... and an abstract class which inherits from the Invoker-interface like the following:
>
> abstract class AbstractInvoker : Invoker {
>
>   private int myInt;
>
>   override void opCall(uint i) { /** do nothing */ }

In an abstract class you can just leave this out. The inheriting class 
will then be checked to implement this.

>
>   void opCall() {
>    opCall(myInt);
>   }
>
> }
>
> I know... I can remove the opCall(uint i) from the interface, but it's needed for some other classes which implements this method. For
> those classes the opCall(uint i)-method is needed.
>
> But... when I now declare a class like this:
>
> class InvokableClass : AbstractInvoker {
>   override void opCall(uint i) {
>    // do something
>   }
> }
>
> and do the following:
>
> void main(string[] args) {
>   InvokableClass() ic = new InvokeableClass();
>   ic();
> }
>
> I always get the following errors:
>
> Error: function InvokableClass.opCall (uint i) is not callable using argument types ().
> Error: expected 1 function arguments, not 0
>
> But I think opCall() is implemented in the abstract class and should be callable using opCall() instead using opCall(uint i)?

Overriding one opCall shadows all other opCalls inherited from the base 
class. This behaviour is like with any method. Write:

override void opCall() {
	super.opCall();
}

to forward to the base class method.
AFAIK it's an anti-hijacking machanism.


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