Foreach with byte problems
Ali Çehreli
acehreli at yahoo.com
Fri Feb 25 13:59:37 PST 2011
On 02/25/2011 10:52 AM, Andrej Mitrovic wrote:
> So I'd like to print all values storable in a byte in hex representation:
>
> import std.stdio;
> void main()
> {
> int counter;
> foreach (byte index; byte.min..byte.max)
> {
> if (!(counter % 4))
> writeln();
>
> writef("%#.2x, ", index);
> counter++;
> }
> }
>
> If you run this, you'll realize that it doesn't print the final 0x7F. This is because in a foreach range literal (is that the correct term?), the left side is inclusive, but the right side isn't.
I've seen the same "problem" with enums.
import std.stdio;
enum E { x, y, z }
void main()
{
foreach (e; E.min .. E.max) {
writeln(e);
}
}
The value 2 is excluded. Of course it's rare to use enums like that in a
foreach loop as their values are not always continuous.
I found out the better solution before sending this message:
foreach (e; __traits(allMembers, E)) {
writeln(e);
}
The difference is, the type of 'e' is string above. Finally, the
following produces integer values:
foreach (e; __traits(allMembers, E)) {
writeln(to!E(e));
}
Ok, good... :)
Ali
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