can I force a parallel foreach to finish?

[McAnany, Charles E]

Hi, all. So I'm getting the classic "concurrency noob" behavior from this code:
    shared int times;    
    int[] iterationRange = new int[2500];
    foreach (pos, ref  i; parallel(iterationRange)){
        times++;
    }
    writeln(times);
}
Prints random numbers near 1,000.
Looking at the documentation for std.concurrency, it appears that when dealing with tasks, you have to yieldForce to get them to finish. Is there a method that blocks until taskPool itself is empty?

I think the problem is not concurrent modification, the foreach just seems to return too early, as seen here:

int times;
void shareAugmenter(){
    bool cont = true;
    while(cont){
        receive( (int i){times++;},
                 (string s){writefln("in the thread %s",times);cont = false;});
    }
}
void main(string[] args){
    
    auto td = spawn(&shareAugmenter);
    int[] iterationRange = new int[2500];
    foreach (pos, ref  i; parallel(iterationRange)){
        td.send(1);
    }
    writeln(times);
    td.send("");
    writeln(times);
prints 
0
0
In the thread 2500

Cheers,
Charles.