private method in interface

[Jonathan M Davis]

On 2011-06-03 19:44, Michael Shulman wrote:
> On Fri, Jun 3, 2011 at 3:07 PM, Jonathan M Davis <jmdavisProg at gmx.com> 
wrote:
> > I'd suggest opening a bug report.
> 
> Okay, will do.
> 
> > Regardless, I would have hoped that you'd get an error at compile
> > time about overriding a non-virtual function if package is
> > non-virtual
> 
> It appears that overriding a non-virtual, non-abstract method (private
> or package) just hides the base-class version when the reference is of
> derived type, exactly as happens in C++ for non-virtual methods.  E.g.
> 
> class A {
>   private void dostuff() { writeln ("In A.dostuff"); }
> }
> 
> class B : A {
>   private void dostuff() { writeln ("In B.dostuff"); }
> }
> 
> void main () {
>   B y = new B();
>   A x = y;
>   y.dostuff();
>   x.dostuff();
> }
> 
> prints
> 
> In B.dostuff
> In A.dostuff
> 
> I would have kind of hoped for a compiler error too, given that C++
> programmers generally seem to feel that overriding non-virtual methods
> in this way is a bad idea.

Try to compile with -w. My guess is that you will get a compiler error. But 
yes, it really should give an error regardless.

- Jonathan M Davis