Breaking the type system needs temporary?

[David Nadlinger]

The result of a cast is not an lvalue.

David


On 6/25/11 7:37 PM, simendsjo wrote:
> I'm calling functions using ParameterTypeTuple. The problem arise when
> the parameters is defined as const/immutable. So I need to break out of
> the type system.
> But I cannot seem to do this without using a temporary variable. Am I
> doing something wrong?
>
> int i = 1;
> const(int*) c;
> //c = &v; // ok - cannot modify const
> int* cp = cast(int*)c;
> cp = &v; // ok - breaking type system
> //(cast(int*)c) = &v; // cannot modify const - shouldn't this work as
> above?