From number of seconds in a day to a formatted time string

Jonathan M Davis jmdavisProg at gmx.com
Tue Jun 12 10:40:24 PDT 2012


On Tuesday, June 12, 2012 19:28:38 TJB wrote:
> I am working with some financial data that comes in binary files.
> It has two fields in particular that I am trying to convert to
> human readable formats. The first is a date string like
> "20060621", which I am able to work with just fine. But then it
> has a field called ttim, which is the number of seconds from
> midnight at which a trade occurred. For example, a trade
> occurring at 28824 seconds in the day would have taken place at
> "8:00:24" (only resolution to the second).
> 
> My question is: how do I convert the number of seconds (like
> 28824) to a formatted time string (like 08:00:24)? I looked in
> std.datetime, but it isn't obvious which functions I should use.
> 
> You help and suggestions are much appreciated!

import std.datetime;
import std.stdio;

void main()
{
 auto ttm = 28824;
 auto duration = dur!"seconds"(ttm);
 auto time = TimeOfDay.init + duration;
 writeln(time.toISOExtString());
}

- Jonathan M Davis


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