From number of seconds in a day to a formatted time string

[TJB]

On Tuesday, 12 June 2012 at 17:40:40 UTC, Jonathan M Davis wrote:
> On Tuesday, June 12, 2012 19:28:38 TJB wrote:
>> I am working with some financial data that comes in binary 
>> files.
>> It has two fields in particular that I am trying to convert to
>> human readable formats. The first is a date string like
>> "20060621", which I am able to work with just fine. But then it
>> has a field called ttim, which is the number of seconds from
>> midnight at which a trade occurred. For example, a trade
>> occurring at 28824 seconds in the day would have taken place at
>> "8:00:24" (only resolution to the second).
>> 
>> My question is: how do I convert the number of seconds (like
>> 28824) to a formatted time string (like 08:00:24)? I looked in
>> std.datetime, but it isn't obvious which functions I should 
>> use.
>> 
>> You help and suggestions are much appreciated!
>
> import std.datetime;
> import std.stdio;
>
> void main()
> {
>  auto ttm = 28824;
>  auto duration = dur!"seconds"(ttm);
>  auto time = TimeOfDay.init + duration;
>  writeln(time.toISOExtString());
> }
>
> - Jonathan M Davis

Awesome! In the D community you get questions answered by the 
library writers!  Thanks so much! This was perfect.

TJB