std.math.sqrt(real x) && std.math.sqrt(float x) overloads

[bearophile]

Tobias Pankrath:

> Shouldn't this just work?
> ...
> Instead it's
> Error: function std.math.sqrt called with argument types:
>         ((int))
> matches both:
>         std.math.sqrt(float x)
> and:
>         std.math.sqrt(real x)

In theory yes, in practice probably it's better for it to not 
compile, given the current situation of the D type system.

Bye,
bearophile
(this is probably one of the less informative answers I've given 
recently)