Can I call the default opAssign after overloading opAssign?

[Rob T]

On Monday, 19 November 2012 at 12:10:32 UTC, Dan wrote:
> [...]
> provide it - you do not need an opAssign at all, as your 
> postblit will be called. I think this is a step up over C++.
>
> The example below prints:
> ----------------------------------------------
> Begin assign
> postblit A
> End assign
> ----------------------------------------------
>
> import std.stdio;
> import std.traits;
>
> struct A {
>   this(this) { c = c.dup; writeln("postblit A"); }
>   char[] c;
>
> }
> struct B { A a; }
> struct C { B b; }
> struct D { C c; }
>
> void main() {
>   D d1, d2;
>   d1.c.b.a.c = ['a','b','c'];
>   writeln("Begin assign");
>   d2 = d1;
>   writeln("End assign");
> }

That's VERY interesting indeed and originally I had no idea it 
would do this without a custom opAssign at each level.

This kind of behavior *really* needs to be documented in precise 
detail, it's rather critical to know.

--rt