access enclosing type from shared static this()

Timon Gehr timon.gehr at gmx.ch
Wed Sep 19 12:52:35 PDT 2012


On 09/19/2012 09:37 PM, "Øivind" wrote:
> I want to access the type of the enclosing struct in in a shared static
> initializer.. How do I do that? The following code will not compile:
>
> mixin template MsgMixin(T ...) {
>    static string getName(this M)() {
>      return M.stringof;
>    }
>    shared static this() {
>      import std.stdio;
>      writeln("register " ~ getName());
>    }
> }
>
> struct MsgTestMsg {
>    mixin MsgMixin!();
> }
>
> I get the following error messages:
>
> src/main.d(40): Error: template main.MsgTestMsg.MsgMixin!().getName does
> not match any function template declaration
> src/main.d(40): Error: template main.MsgTestMsg.MsgMixin!().getName(this
> M) cannot deduce template function from argument types !()()
>
> If not possible, just getting the name of the enclosing struct would
> help a lot!
>
> -Øivind
>

use typeof(this), eg:

mixin template MsgMixin(T ...) {
     shared static this() {
         import std.stdio;
         writeln("register " ~ typeof(this).stringof);
     }
}



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