map with void fun
bearophile
bearophileHUGS at lycos.com
Sat Apr 6 14:40:35 PDT 2013
cal:
> Should the code below print anything (it currently doesn't)?
> I'm not sure I understand map:
>
> import std.stdio, std.algorithm;
>
> void main() {
> int[] a = [1,2,3,4,5];
> auto r = a.map!( i => writeln(i) );
> while(!r.empty) r.popFront();
> }
The code is working as requested. But there are problems at
various levels.
First, to see the side effects you have also to call front:
import std.stdio, std.algorithm;
void main() {
auto a = [1, 2, 3, 4, 5];
auto r = a.map!(x => writeln(x));
while(!r.empty) {
r.front;
r.popFront;
}
}
That prints:
1
2
3
4
5
But this is wrong still. map() is a higher order function, it's
meant to take a function and an iterable and produce a new lazy
iterable that contains the ordered results of applying the given
function on each item. writeln() returns nothing (void, it's a
type with just one value, void itself).
So one more meaningful way to do that is:
import std.stdio, std.algorithm, std.conv;
void main() {
auto a = [1, 2, 3, 4, 5];
a.map!text.writeln;
}
That prints:
["1", "2", "3", "4", "5"]
But writeln is well designed, so it's able to take a range, so
this is better:
import std.stdio, std.algorithm;
void main() {
auto a = [1, 2, 3, 4, 5];
a.writeln;
}
Bye,
bearophile
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