Type inference + forwarding lambda predicate
Jacob Carlborg
doob at me.com
Fri Jan 4 08:06:38 PST 2013
The following code results in a Segmentation fault: 11. The reason seems
to be because "any" is called indefinitely. But if I don't use type
inference for the lambda it works correctly.
import algorithm = std.algorithm;
bool any (alias predicate, Range) (Range range)
{
return algorithm.any!(predicate)(range);
}
void main ()
{
auto arr = ["foo"];
any!(e => e == "asd")(arr); // segfault
// any!((string e) => e == "asd")(arr); // works
}
Am I doing something wrong or is this a bug?
--
/Jacob Carlborg
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