is(...) with alias this

Philippe Sigaud philippe.sigaud at gmail.com
Sat Jan 5 14:09:36 PST 2013


I think the alias this transformation is done 'before' any usual
conversion. I guess it's a real replacement inside the code (I'm not sure
how to explain my feeling).

But in any case, since OhWhy!(float) type is ... OhWhy!(float), I agree
this should fail.
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