Issue with char and string overlap
anonymous
anonymous at example.com
Fri Jul 19 10:40:20 PDT 2013
On Friday, 19 July 2013 at 17:18:00 UTC, JS wrote:
> both functions work separately but when i uncomment the string
> version I get an error about the string version shadowing.
>
> import std.stdio, std.cstream;
>
> string[] split(T)(string s, T d) if (is(T == char) || is(T ==
> string))
> {
> int i = 0, oldj = 0; bool ok = true;
i and oldj should probably be size_t. The same for other ints
throughout.
> string[] r;
> foreach(j, c; s)
The first j is declared here.
> {
> static if (is(T == char))
> {
> if (c == d)
> {
> if (!ok) { oldj++; continue; }
> if (r.length <= i) r.length += 5;
> r[i] = s[oldj..j];
> i++; oldj = j+1;
> ok = false;
> } else if (!ok) ok = true;
> }
> else if (is(T == string))
> {
> /*
> for(int j = 0; j < s.length - d.length; j++)
This j would shadow the one above. Just choose another name.
> {
> if (s[j..j + d.length] == d)
> {
> if (!ok) { oldj++; continue; }
> if (i == r.length) r.length += 5;
> r[i] = s[oldj..j - d.length + 1];
> i++; oldj = j + d.length;
> ok = false;
> } else if (!ok) ok = true;
>
> }
> */
> }
> }
> if (oldj < s.length)
> {
> if (r.length <= i) r.length++;
> r[i] = s[oldj..$];
> i++;
> }
> r.length = i;
> return r;
> }
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