Array-wise expressions and range checking

Jonathan M Davis jmdavisProg at gmx.com
Sun Jun 16 02:35:06 PDT 2013


On Sunday, June 16, 2013 11:09:27 Alexander wrote:
> Hello,
> 
> I'm reading "The D programming language", part "4.1.7 Array-wise
> Expressions".
> 
> It states that
> 
> "The effect of an array-wise expression is that of a loop
> assigning each element of the
> left-hand side in turn with the corresponding index of the
> right-hand side. For example,
> the assignment
> 
> auto a = [1.0, 2.5, 3.6];
> auto b = [4.5, 5.5, 1.4];
> auto c = new double[3];
> c[] += 4 * a[] + b[];
> 
> is the same as
> 
> foreach (i; 0 .. c.length) {
>      c[i] += 4 * a[i] + b[i];
> }"

Yeah, but as you failed to set any of c's elements to anything first, and 
they're default initialized to NaN, and all math done on NaN results in NaN, 
so none of c's elements will have changed in your example.

> So I assume that the following code should generate runtime
> exception during evaluation of c[2] = b[2] + a[2], but it doesn't
> happen.
>
> auto b = [1, 2];
> auto a = [2, 3, 4];
> int c [] = new int[3];
> c[] = b[] + a[];
> return c;
> 
> Is it an intended behaviour or a compiler bug?

That does look like a compiler bug. It should throw a RangeError, because a 
and b have different lengths, but it isn't. Please report it:

http://d.puremagic.com/issues

- Jonathan M Davis


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