std.process spawnShell/pipeShell dont capture output of the shell

[Jesse Phillips]

On Wednesday, 9 October 2013 at 11:22:26 UTC, Colin Grogan wrote:
> "
> ~/test$ ./mess ls
> Executing: ls
> STDOUT: mess
> STDOUT: text.txt
>
> "
> Thats all fine, however, I'd expect it to print another 
> "~/test$" at the end, as if its an interactive shell waiting 
> for input.

It is extracting the output of the program, 99.9% of the time 
this is what everyone wants and including the shells behavior 
would be terrible.

If you run bash, then it is going to be waiting for stdin so 
you'd need to pass it "ls" and "exit" to get the output and quit. 
I'm not sure this would get you want you wanted.