does cast make an lvalue appear to be an rvalue
Maxim Fomin
maxim at maxim-fomin.ru
Wed Oct 16 11:09:53 PDT 2013
On Wednesday, 16 October 2013 at 17:05:25 UTC, Daniel Davidson
wrote:
> The code below fails to compile due to the last line. I was
> hoping casting away immutable would allow the call to foo. I
> think it is not accepted because of the rval to ref issue. If
> that is the case, how can foo be called by casting?
>
> I'm not a fan of casting but I'm finding cases where it is the
> only recourse to create immutable data using impure functions
> that should be pure.
>
> Thanks
> Dan
>
> import std.conv;
>
> struct T {
> int[] i;
> string[string] ss;
> }
>
> void foo(ref T t) {
> }
>
> void main() {
> T t1;
> auto t2 = immutable T();
> foo(t1);
> foo(cast()t2);
> }
foo([cast()t2][0]);
(It would be good to have compound literals like in C)
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