Task to throw away string parts, use joiner and splitter not very successful

[Rémy Mouëza]

The popBack function returns the element you are removing from the 
array, not the array itself, thus "breaking" the chaining of function.

On 01/01/2014 08:36 AM, Dfr wrote:
> This is interesting, why i can't just do it simpler way ?
>
> "this.is.a.string"
>               .splitter (".")
>               .popBack
>               .joiner (".")
>               .array
>               .writeln;
>
>
> Because creating an extra function is not desired.
>
>> As Chris wrote, using double quotes to use strings instead of char
>> solves the typing issse.
>>
>> I'd also suggest the following alternative, if you're going to discard
>> a lot of last elements in your code:
>>     import std.stdio;
>>     import std.algorithm;
>>     import std.array;
>>     import std.range;
>>
>>     /// Return seq without its last element.
>>     auto poppedBack (T) (T seq) if (isInputRange!T) {
>>         seq.popBack; // Discards the last element.
>>         return seq;
>>     }
>>
>>     void main () {
>>         // Prints "this.is.a".
>>         "this.is.a.string"
>>             .splitter (".")
>>             .poppedBack
>>             .joiner (".")
>>             .array
>>             .writeln;
>>     }
>>
>>
>> On 12/31/2013 09:57 PM, Chris Cain wrote:
>>> On Tuesday, 31 December 2013 at 20:49:55 UTC, Dfr wrote:
>>>> Hello, i have string like "this.is.a.string" and want to throw away
>>>> some parts separated by dots, here is first attempt:
>>>>
>>>> name = "this.is.a.string"; // <-- want to make "this.is.a" from this
>>>> auto nameparts = splitter(name, '.');
>>>> auto name1 = joiner(nameparts[0 .. $-1], '.');
>>>>
>>>> And got this error: "Error: Result cannot be sliced with []"
>>>>
>>>> So, kinda fixed it (correct way?):
>>>>
>>>> name = "this.is.a.string";
>>>> auto nameparts = splitter(name, '.').array;
>>>> auto name1 = joiner(nameparts[0 .. $-1], '.');
>>>>
>>>> got this:
>>>>
>>>> Error: template std.algorithm.joiner does not match any function
>>>> template declaration. Candidates are:
>>>> /usr/include/dmd/phobos/std/algorithm.d(2846):
>>>> std.algorithm.joiner(RoR, Separator)(RoR r, Separator sep) if
>>>> (isInputRange!RoR && isInputRange!(ElementType!RoR) &&
>>>> isForwardRange!Separator && is(ElementType!Separator :
>>>> ElementType!(ElementType!RoR)))
>>>>
>>>> Stuck here, thank you for any help.
>>>
>>> From your error message: isForwardRange!Separator
>>>
>>> Your separator is a character, which isn't a forward range. Try this:
>>> `auto name1 = joiner(nameparts[0 .. $-1], ".");`