Task to throw away string parts, use joiner and splitter not very successful
Rémy Mouëza
remy.moueza at gmail.com
Wed Jan 1 08:31:43 PST 2014
You can use `std.conv.to` to convert the dchar[] back to a string,
adding `.to!string` at the end of the dchar[] array you want to convert.
Also not that there exists two similar functions to the lazy evaluated
splitter() and joiner() in std.array: the eagerly evaluated split() and
join(); being eager make the code looks more straightforward (no
`.array` or `.to!string`).
import std.stdio;
import std.array;
import std.algorithm;
void eager () {
string name = "thiš.ìs.à.çtriñg";
auto parts = name.split (".");
parts.popBack;
auto cut = parts.join (".");
cut.writeln;
}
void lazy_ () {
string name = "thiš.ìs.à.çtriñg";
auto parts = name.splitter (".");
parts.popBack;
auto cut = parts.joiner (".").array.to!string;
cut.writeln;
}
void main () {
eager ();
lazy_ ();
}
The program prints:
thiš.ìs.à
thiš.ìs.à
On 01/01/2014 08:40 AM, Dfr wrote:
> And one more problem here:
>
> string name = "test";
> auto nameparts = splitter(name, '.');
> writeln(typeof(joiner(nameparts, ".").array).stringof);
>
> This prints "dchar[]", but i need char[] or string, how to get my
> 'string' back ?
>
>
> On Tuesday, 31 December 2013 at 20:49:55 UTC, Dfr wrote:
>> Hello, i have string like "this.is.a.string" and want to throw away
>> some parts separated by dots, here is first attempt:
>>
>> name = "this.is.a.string"; // <-- want to make "this.is.a" from this
>> auto nameparts = splitter(name, '.');
>> auto name1 = joiner(nameparts[0 .. $-1], '.');
>>
>> And got this error: "Error: Result cannot be sliced with []"
>>
>> So, kinda fixed it (correct way?):
>>
>> name = "this.is.a.string";
>> auto nameparts = splitter(name, '.').array;
>> auto name1 = joiner(nameparts[0 .. $-1], '.');
>>
>> got this:
>>
>> Error: template std.algorithm.joiner does not match any function
>> template declaration. Candidates are:
>> /usr/include/dmd/phobos/std/algorithm.d(2846):
>> std.algorithm.joiner(RoR, Separator)(RoR r, Separator sep) if
>> (isInputRange!RoR && isInputRange!(ElementType!RoR) &&
>> isForwardRange!Separator && is(ElementType!Separator :
>> ElementType!(ElementType!RoR)))
>>
>> Stuck here, thank you for any help.
>
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