Question about iteger literals

[bearophile via Digitalmars-d-learn]

Uranuz:

> But I don't understand why in expression where both of 
> arguments have type char:
> 	return c - '0';
> I have resulting type int. It's very strange for me and looks 
> very buggy)

In D operations among chars return a int. The same happens in 
C/C++.

If you subtract a char from a char in general you can have a 
negative result, that can't fit in a char. So what's buggy is 
your thinking.

Bye,
bearophile