cannot sort an array of char

[via Digitalmars-d-learn]

On Tuesday, 11 November 2014 at 13:20:53 UTC, Steven 
Schveighoffer wrote:
> On 11/11/14 6:07 AM, Ivan Kazmenko wrote:
>> IK>> Why is "char []" so special that it can't be sorted?
>>
>> SS> Because sort works on ranges, and std.range has the view 
>> that
>> SS> char[] is a range of dchar without random access. Nevermind
>> SS> what the compiler thinks :)
>> SS>
>> SS> I believe you can get what you want with
>> SS> std.string.representation:
>> SS>
>> SS> import std.string;
>> SS>
>> SS> sort(c.representation);
>>
>> Thank you for showing a library way to do that.
>> I ended up with using a cast, like "sort (cast (ubyte []) c)".
>> And this looks like a safe way to do the same.
>
> It's safe but be careful. For instance, if c becomes an 
> immutable(char)[] or const(char)[], then you will have 
> undefined behavior. If you use the representation, it will 
> properly reject this behavior.
>
>> Now, std.utf's byCodeUnit and std.string's representation seem 
>> like
>> duplicate functionality, albeit with different input and 
>> output types
>> (and bugs :) ).
>
> No, byCodeUnit is not an array, it's a range of char. They 
> solve different problems, and mean different things.
>
> Note, byCodeUnit should work for sort, I'm surprised it doesn't.

That's what he meant by "bugs" :-P

But it's been fixed already, thanks to H.S. Teoh.